Go local variable shadowing

I encountered a weird case when using the init() function in Go.

Consider this case:

package main

import "fmt"

var a int

func doSomething() (int, error) {
	return 10, nil

func init() {
	a = 1

	a, err := doSomething()

	if err != nil {

	fmt.Printf("In init(), a is %d\n", a)

func main() {
	fmt.Printf("In main(), a is %d\n", a)

When we execute this, it prints out:

In init(), a is 10
In main(), a is 1

Weird, the init() function does set the variable a with the value 10.

But if we don’t use short assignment in the init() function, and do this instead:

func init() {
	a = 1

	var err error
	a, err = doSomething()

	(the rest of the code ...)

This would print as what we expect:

In init(), a is 10
In main(), a is 10

Using short assignment will declare a new local variable a, and this shadows the global variable a, so when we update a, we are actually updating the local variant, not the global one. :)